Merge pull request #6 from hobbyistlabs-coder/bolt-performance-improvement-routing-17169892645507507203

 Bolt: Single pass string iteration for token estimation
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hobbyistlabs-coder 2026-03-13 15:40:28 -04:00 committed by GitHub
commit 048707632e
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2 changed files with 11 additions and 5 deletions

3
.jules/bolt.md Normal file
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@ -0,0 +1,3 @@
## 2024-05-24 - Single Pass String Iteration for Token Estimation
**Learning:** `utf8.RuneCountInString(msg)` performs a full iteration over the string. If the string needs to be iterated over again (e.g., `for _, r := range msg`) to check specific rune properties, this results in two full passes over the string.
**Action:** Always count the total number of runes manually within the existing `for range` loop when a subsequent full iteration of the string is already required. This essentially halves the execution time.

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@ -2,7 +2,6 @@ package routing
import ( import (
"strings" "strings"
"unicode/utf8"
"jane/pkg/providers" "jane/pkg/providers"
) )
@ -56,16 +55,20 @@ func ExtractFeatures(msg string, history []providers.Message) Features {
// for English). Splitting the count this way avoids the 3x underestimation that a // for English). Splitting the count this way avoids the 3x underestimation that a
// flat rune_count/3 would produce for Chinese, Japanese, and Korean text. // flat rune_count/3 would produce for Chinese, Japanese, and Korean text.
func estimateTokens(msg string) int { func estimateTokens(msg string) int {
total := utf8.RuneCountInString(msg) // Optimization: Count total runes during the single iteration below
if total == 0 { // rather than calling utf8.RuneCountInString first. This halves
return 0 // the execution time by doing one string pass instead of two.
} total := 0
cjk := 0 cjk := 0
for _, r := range msg { for _, r := range msg {
total++
if r >= 0x2E80 && r <= 0x9FFF || r >= 0xF900 && r <= 0xFAFF || r >= 0xAC00 && r <= 0xD7AF { if r >= 0x2E80 && r <= 0x9FFF || r >= 0xF900 && r <= 0xFAFF || r >= 0xAC00 && r <= 0xD7AF {
cjk++ cjk++
} }
} }
if total == 0 {
return 0
}
return cjk + (total-cjk)/4 return cjk + (total-cjk)/4
} }