fix(cron): publish agent response to outbound bus after ProcessDirectWithChannel

ProcessDirectWithChannel bypasses the AgentLoop bus, so the Run() loop's
PublishOutbound never fires. The response was silently discarded with _ = response,
causing cron-triggered agent replies to never reach the Telegram channel.

Fix by explicitly calling PublishOutbound with the response when non-empty,
consistent with the deliver=true and command execution paths.

pkg/tools/cron.go

@@ -327,7 +327,12 @@ func (t *CronTool) ExecuteJob(ctx context.Context, job *cron.CronJob) string {
 		return fmt.Sprintf("Error: %v", err)
 	}
 
-	// Response is automatically sent via MessageBus by AgentLoop
-	_ = response // Will be sent by AgentLoop
+	if response != "" {
+		t.msgBus.PublishOutbound(bus.OutboundMessage{
+			Channel: channel,
+			ChatID:  chatID,
+			Content: response,
+		})
+	}
 	return "ok"
 }